40y^2-205y+25=0

Solution for 40y^2-205y+25=0 equation:

40y^2-205y+25=0

a = 40; b = -205; c = +25;
Δ = b2-4ac
Δ = -2052-4·40·25
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-205)-195}{2*40}=\frac{10}{80}
=1/8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-205)+195}{2*40}=\frac{400}{80}
=5
$